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5x^2+16x-54=-9
We move all terms to the left:
5x^2+16x-54-(-9)=0
We add all the numbers together, and all the variables
5x^2+16x-45=0
a = 5; b = 16; c = -45;
Δ = b2-4ac
Δ = 162-4·5·(-45)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-34}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+34}{2*5}=\frac{18}{10} =1+4/5 $
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